Showing posts with label EQ. Show all posts
Showing posts with label EQ. Show all posts

Saturday, November 5, 2011

\( \equiv \) Theorem 2: p \( \equiv \) p

\( \hspace{2 cm}\) p \( \equiv \) p
\( \hspace{0.5 cm} = \) the \( \equiv \) Identity Axiom. \( p \equiv p \equiv true \)
\( \hspace{2 cm}\) true. QED

\( \equiv \) Theorem 1: true

\( \hspace{2 cm} true \equiv p \equiv p \), Axiom, Identity of \( \equiv \),
\( \hspace{0.5 cm} = \) Leibniz, E = Identity Axiom above, \(p = p \equiv p, q = true \)
\( \hspace{2 cm} true \equiv true \)
\( \hspace{0.5 cm} \equiv \) Axiom, Identity of \( \equiv \),\(true \equiv p \equiv p \),
\( \hspace{2 cm} \) true

EQ Axioms and Advice

(1) Axiom: Associativity of \(\equiv\): p \(\equiv\) (q \(\equiv\) r) \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) (p \(\equiv\) q ) \(\equiv\) r

(2) Axiom: Symmetry of \(\equiv\): p \(\equiv\) q \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) q \(\equiv\) p

(3) Axiom: Identity of \(\equiv\): true \(\equiv\) q \(\equiv \) q

Wednesday, October 5, 2011

EQ 15 Equivalence and True

(1) Axiom: Associativity of \(\equiv\): p \(\equiv\) (q \(\equiv\) r) \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) (p \(\equiv\) q ) \(\equiv\) r

(2) Axiom: Symmetry of \(\equiv\): p \(\equiv\) q \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) q \(\equiv\) p

(3) Axiom: Identity of \(\equiv\): true \(\equiv\) q \(\equiv \) q

(4) Theorem: true

(5) Reflexivity of \(\equiv\): p \(\equiv\) p

EQ 14 Negation, Inequivalence, False

(1) Axiom: Definition of false: false \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) \(\neg\) true

(2) Axiom: Distributivity of \(\frac{\neg}{\equiv}\): \(\neg\) (p \(\equiv\) q) \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) \(\neg\)p \(\equiv\) q

(3) Axiom: Definition \(\not\equiv\): (p \(\not\equiv\) q) \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) \(\neg\)(p \(\equiv\) q)

(4) Theorem: \(\neg\)p \(\equiv\) q \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) p \(\equiv\) \(\neg\)q

(5) Theorem: Double Negation: \(\neg\)\(\neg\)p \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) p

(6) Theorem: Negation of false: \(\neg\)false \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) true

(7) Theorem: (p \(\not\equiv\) q) \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) \(\neg\)p \(\equiv\) q

(8) Theorem: \(\neg\)p\(\equiv\)p\(\equiv\)false

(9) Theorem: Symmetry of \(\not\equiv\): p \(\not\equiv\) q \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) q \(\not\equiv\) p

(10) Theorem: Associativity of \(\not\equiv\): (p \(\not\equiv\) (q \(\not\equiv\) r)) \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) ((p \(\not\equiv\) q ) \(\not\equiv\) r)

(11) Mutual Associativity: (p \(\not\equiv\) (q \(\equiv\) r)) \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) ((p \(\not\equiv\) q ) \(\equiv\) r)

(12) Mutual Interchangability: p \(\not\equiv\) q \(\equiv\) r \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) p \(\equiv\) q \(\not\equiv\) r

EQ 13 Disjunction

(1) Axiom Symmetry of \(\vee\): p \(\vee\) q \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) q \(\vee\) p

(2) Axiom Associativity of \(\vee\): p \(\vee\) (q \(\vee\) r) \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) (p \(\vee\) q ) \(\vee\) r

(3) Axiom Idempotency of \(\vee\): p \(\vee\) p \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) p

(4) Axiom Distributivity of \(\frac{\vee}{\equiv}\): p \(\vee\) ( q \(\equiv\) r) \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) (p \(\vee\) q) \(\equiv\) (p \(\vee\) r)

(5) Axiom Excluded Middle p \(\vee\) \(\neg\)p

(6) Theorem Zero of \(\vee\): p \(\vee\) true \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) true

(7) Theorem Identity of \(\vee\) p \(\vee\) false \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) p

(8) Theorem Distributivity of \(\frac{\vee}{\vee}\): p \(\vee\) ( q \(\vee\) r) \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) (p \(\vee\) q) \(\vee\) (p \(\vee\) r)

(9) Theorem p \(\vee\) q \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) p \(\vee\) \(\neg\)q \(\equiv\) p

EQ 12 Conjunction

(1) Axiom: Golden Rule: p \(\wedge\) q \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) p \(\vee\) q \(\equiv\) p \(\equiv\) q

(2) Theorem Symmetry of \(\wedge\): p \(\wedge\) q \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) q \(\wedge\) p

(3) Theorem Associativity of \(\wedge\): p \(\wedge\) ( q \(\wedge\) r) \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) (p \(\wedge\) q) \(\wedge\) r

(4) Theorem Idempotency of \(\wedge\): p \(\wedge\) p \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) p


(5) Theorem Identity of \(\wedge\): p \(\wedge\) true \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) p


(6) Theorem Zero of \(\wedge\): p \(\wedge\) false \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) false


(7) Theorem Distributivity of \(\frac{\wedge}{\wedge}\): p \(\wedge\) ( q \(\wedge\) r) \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) (p \(\wedge\) q) \(\wedge\) (p \(\wedge\) r)

(8) Theorem Contradiction: p \(\wedge\) \(\neg\)p \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) false

(9) Theorem Absorption 1: p \(\wedge\) ( p \(\vee\) q) \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) p


(10) Theorem Absorption 2: p \(\wedge\) (\(\neg\) p \(\vee\) q) \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) p \(\wedge\) q

(11) Theorem Absorption 3: p \(\vee\) ( p \(\wedge\) q) \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) p

(12) Theorem Absorption 4: p \(\vee\) (\(\neg\) p \(\wedge\) q) \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) p \(\vee\) q

(13) Theorem Distributivity of \(\frac{\wedge}{\vee}\): p \(\wedge\) ( q \(\vee\) r) \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) (p \(\wedge\) q) \(\vee\) (p \(\wedge\) r)

(14) Theorem Distributivity of \(\frac{\vee}{\wedge}\): p \(\vee\) ( q \(\wedge\) r) \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) (p \(\vee\) q) \(\wedge\) (p \(\vee\) r)

(15) Theorem De Morgan 1 \(\neg\) (p \(\wedge\) q) \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) (\(\neg\)p \(\vee\)\(\neg\) q)

(16) Theorem De Morgan 2 \(\neg\) (p \(\vee\) q) \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) (\(\neg\)p \(\wedge\)\(\neg\) q)

(17) Theorem p \(\wedge\) q \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) p \(\wedge\) \(\neg\)q \(\equiv\)\(\neg\) p

(18) Theorem p \(\wedge\) ( q \(\equiv\) r) \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) p \(\wedge\) q \(\equiv\) p \(\wedge\) r \(\equiv\) p

(19) Theorem p \(\wedge\) ( q \(\equiv\) p) \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) p \(\wedge\) q

(20) Theorem Replacement ( p \(\equiv\) q) \(\wedge\) ( r \(\equiv\) p) \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) ( p \(\equiv\) q) \(\wedge\) ( r \(\equiv\) q)

(21) Theorem Definition of \(\equiv\): ( p \(\equiv\) q) \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) ( p \(\wedge\) q) \(\vee\) (\(\neg\) p \(\wedge\) \(\neg\)q)

(22) Theorem Exclusive Or: ( p \(\not\equiv\) q) \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) ( p \(\wedge\) \(\neg\)q) \(\vee\) (\(\neg\) p \(\wedge\) q)


(23) Theorem (p \(\wedge\) q) \(\wedge\) r \( \hspace{0.2 cm} \equiv \hspace{0.2 cm} \) p \(\equiv\) q \(\equiv\) r \(\equiv\) p \(\vee\) q \(\equiv\) q \(\vee\) r \(\equiv\) p \(\vee\) r \(\equiv\) p \(\vee\) q \(\vee\) r

EQ 11 Existential Quantification

(0) Notation (\(\vee\) x | R : P ) \(\hspace{0.5 cm} \equiv \hspace{0.5 cm}\) (\(\exists\) x | R : P )

(1) Axiom: Generalized deMorgan: (\(\exists\) x | R : P) \(\hspace{0.5 cm} \equiv \hspace{0.5 cm}\) \(\neg\)( \(\forall\) x | R : \(\neg\) P)

(2) Theorem: Generalized deMorgan 1 : \(\neg\) (\(\exists\) x | R : \(\neg\)P) \(\hspace{0.5 cm} \equiv \hspace{0.5 cm}\) ( \(\forall\) x | R : P)

(3) Theorem: Generalized deMorgan 2 : \(\neg\) (\(\exists\) x | R : P) \(\hspace{0.5 cm} \equiv \hspace{0.5 cm}\) ( \(\forall\) x | R : \(\neg\) P)

(4) Theorem: Generalized deMorgan 3 : (\(\exists\) x | R : \(\neg\) P) \(\hspace{0.5 cm} \equiv \hspace{0.5 cm}\) \(\neg\) ( \(\forall\) x | R : P)

(5) Theorem: Trading 1: (\(\exists\) x | R : P) \(\hspace{0.5 cm} \equiv \hspace{0.5 cm}\) ( \(\exists\) x | : R \(\wedge\) P)

(6) Theorem: Trading 2: (\(\exists\) x | S \(\wedge\) R : P) \(\hspace{0.5 cm} \equiv \hspace{0.5 cm}\) ( \(\exists\) x | S : R \(\wedge\) P)

(7) Theorem: Distributivity \(\frac{\wedge}{\exists}\) (\(\exists\) x | R : P) \(\wedge\) Q \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) (\(\exists\) x | R : P \(\wedge\) Q)
not-occurs-free(x,Q)

(8) Theorem: (\(\exists\) x | R : P) \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) (\(\exists\) x |: R ) \(\wedge\) P
not-occurs-free(x,P)

(9) Theorem: Distributivity \(\frac{\vee}{\exists}\) (\(\exists\)x |:R) \( \Rightarrow \) [(\(\exists\) x | R : P \(\vee\) Q)] \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) (\(\exists\) x | R : P) \(\vee\) Q]
not-occurs-free(x,Q)

(10) Theorem: (\(\exists\) x | R : false) \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) false

(11) Theorem: Range Weakening: (\(\exists\) x | R : P) \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) (\(\exists\) x | R \(\vee\) S : P)

(12) Theorem: Body Weakening: (\(\exists\) x | R : P) \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) (\(\exists\) x | R : P \(\vee\) Q)

(13) Theorem: Monotonicity of \(\exists\)
\(\exists\) is monotonic in both body and range
(a) (\(\forall\) x | R : A \( \Rightarrow \) B ) \(\hspace{0.2 cm} \Rightarrow \hspace{0.2 cm}\) [ (\(\exists\) x | A : P) \( \Rightarrow \) (\(\exists\) x | B : P)]
(b) (\(\forall\) x | R : A \( \Rightarrow \) B ) \(\hspace{0.2 cm} \Rightarrow \hspace{0.2 cm}\) [ (\(\exists\) x | R : A) \( \Rightarrow \) (\(\exists\) x | R : B)]

(14) Theorem: P[ x := e] \(\hspace{0.2 cm} \Rightarrow \hspace{0.2 cm}\) (\(\exists\) x |: P)

(15) Theorem: Interchange of Quantifications
(\(\exists\) x | R (\(\forall\) y | S : P)) \(\hspace{0.2 cm} \Rightarrow \hspace{0.2 cm}\) (\(\forall\) y | S (\(\exists\) x | R : P))
not-occurs-free (x,S) \(\wedge\) not-occurs-free(y, R)

Note: only when \(\exists\) encloses \(\forall\). The implication doesn't hold the other way.

(16) Meta Theorem Witness:
(\(\exists\) x | R : P) \(\Rightarrow\) Q is a theorem \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) (R \(\wedge\) P)[\(x\) := \(\hat{x}\)] \(\Rightarrow\) Q is a theorem,
not-occurs-free(\(\hat{x}\), [P,Q,R])
(a) often used when (\(\exists\) x | R : P) is known and need to prove Q.
(b) with multiple statements, use distinct witnesses

EQ 10 Universal Quantification

(0) Notation: (\(\wedge\) x | R : P) \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) (\(\forall\) x | R : P)

(1) Axiom: Trading: (\(\forall\) x | R : P) \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) (\(\forall\) x |: R \(\Rightarrow\) P)

Trading Theorems

(2) Theorem (\(\forall\) x | R : P) \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) (\(\forall\) x |: \(\neg\)R \(\vee\) P)

(3)Theorem (\(\forall\) x | R : P) \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) (\(\forall\) x |: R \(\vee\) P \(\equiv\) P)

(4)Theorem (\(\forall\) x | R : P) \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) (\(\forall\) x |: R \(\wedge\) P \(\equiv\) R)

(5) Theorem (\(\forall\) x | R \(\wedge\) S : P) \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) (\(\forall\) x | S : R \(\Rightarrow\) P)

(6) Theorem (\(\forall\) x | R \(\wedge\) S : P) \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) (\(\forall\) x | S : \(\neg\)R \(\vee\) P)

(7)Theorem (\(\forall\) x | R \(\wedge\) S : P) \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) (\(\forall\) x | S : R \(\vee\) P \(\equiv\) P)

(8)Theorem (\(\forall\) x | R \(\wedge\) S: P) \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) (\(\forall\) x | S : R \(\wedge\) P \(\equiv\) R)

(9) Axiom: Distributivity \(\frac{\vee}{\forall}\) Q \(\vee\) (\(\forall\) x | R : P) \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) (\(\forall\) x | R : P \(\vee\) Q)
not-occurs-free(x,Q)

(10)Theorem: (\(\forall\) x | R :P) \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) (\(\forall\) x |: \( \neg \)R) \(\vee\) P
not-occurs-free(x,P)

(11) Theorem: Distributivity \(\frac{\wedge}{\forall}\) (\(\exists\)x |:R) \( \Rightarrow \) [(\(\forall\) x | R : P \(\wedge\) Q)] \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) (\(\forall\) x | R : P) \(\wedge\) Q]
not-occurs-free(x,Q)

Be careful using this theorem. A conjunct can be moved outside the scope of the quantification only if the Range is not everywhere false

(12) Theorem: (\( \forall \) x | R : true) \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) true

(13) Theorem: (\( \forall \) x | R : P \(\equiv\) Q) \(\hspace{0.2 cm} \Rightarrow \hspace{0.2 cm}\) [(\( \forall \) x | R : P ) \(\Rightarrow\) (\( \forall \) x | R : Q ) ]

(14) Theorem: Range Weakening/Strengthening (\( \forall \) x | R \(\vee\) S : P ) \(\hspace{0.2 cm} \Rightarrow \hspace{0.2 cm}\) (\( \forall \) x | R : P )

(15) Theorem: Body Weakening/Strengthening (\( \forall \) x | R : P \(\wedge\) Q ) \(\hspace{0.2 cm} \Rightarrow \hspace{0.2 cm}\) (\( \forall \) x | R : P )

(16) Theorem: Monotonicity of \(\forall\):
(a) \(\forall\) is antimonotonic in its range: (\(\forall\) x | R : A \(\Rightarrow\) B ) \(\hspace{0.2 cm} \Rightarrow \hspace{0.2 cm}\) [(\(\forall\) x | A : P ) \(\Leftarrow\) (\(\forall\) x | B : P)]
(b) \(\forall\) is monotonic in its body: (\(\forall\) x | R : A \(\Rightarrow\) B ) \(\hspace{0.2 cm} \Rightarrow \hspace{0.2 cm}\) [(\(\forall\) x | R : A ) \(\Rightarrow\) (\(\forall\) x | R : B)]

(17) Instantiation (\( \forall \) x |: P) \(\hspace{0.2 cm} \Rightarrow \hspace{0.2 cm}\) P [x := e]

(18) MetaTheorem: P is a theorem \( \equiv \) (\(\forall\) x |: P) is a theorem

EQ 9 Quantification

(1) Monoids And Abelian Monoids

Binary Operator \( \star \) is associative and has an identity \( \equiv \) it is a monoid. If it is also symmetric, it is an abelian monoid.

In the following the \( \star \) represents an operator that is an abelian monoid. All theorems don't strictly need the "abelian-ness", but the operators we deal with are all abelian, so the assumption does no harm.

(2) General Form of Quantification

( \( \star \) x:type1, y:type2 ..) | Range:\( \mathcal{B} \) : Predicate:type3)

x,y,... are bound variables or 'dummmies'
the Predicate is also known as the "body".

(3) Definition of 'free'

(a) The *occurrence* of i, in an expression i is free
(b) If an occurrence of a variable i in expression E is free, then so is the occurrence in (E), function application arguments f(....E...) [note: binary operators are considered function applications)[, (\( \star \)x|E:P) and (\( \star \)x|R:E) (as long as i is not one of the variables in the dummy list x.)

(4) Definition of 'bound'

(a) If an occurrence of a variable i in expression E is free, then that occurrence is bound to dummy i in (\( \star \)x|E:P) and ( \(\star \)x|R:E) if i occurs in dummy list x.

(b) If an occurrence of i is bound in expression E, then it is also bound to the same dummy in (E), function application arguments f(....E...) [note: binary operators are considered function applications)], (\( \star \)x|E:P) and (\( \star \)x|R:E)

(5) Definition of occurs-free and not-occurs-free

occurs-free(v,e) is defined to mean that at least one variable from the list-of-variables v occurs free in at least one expression in list of expressions v

not-occurs-free(v,e) \( \equiv \) \( \neg \)occurs-free(v,e) \( \equiv \) no variable in list-of-variables v occurs free in any of the expressions in list-of-expressions e

(6) Textual Substitution

Extending textual substitution to quantified statements

( \(\star\) x | R : P)[y := F] \( \hspace{0.2 cm}\equiv\hspace{0.2 cm} \) \( (\star\) x | R[y := F] : P[y := F]),

given not-occurs-free(x,[y,F])), iow none of the bound variables is free on either side of the := . If a bound variable does occur free on either side of :=, replace *the bound variable* with a fresh variable j. This ensures that a free variable in the textual substitution y := F does not become bound.

Extending Leibniz inference rule to handle substitution of either side of an equality into a quantified statement

(7) Leibniz 1

\( \frac{A\hspace{0.2 cm}=\hspace{0.2 cm}B}{(\star x |R [z:=A]: P ) \hspace{0.2 cm}=\hspace{0.2 cm} (\star x |R [z:=B]: P )} \)

(8) Leibniz 2

\( \frac{R\hspace{0.2 cm}\Rightarrow\hspace{0.2 cm}A\hspace{0.2 cm}=\hspace{0.2 cm}B}{(\star x |R : P[z:=A] ) \hspace{0.2 cm}=\hspace{0.2 cm} (\star x |R : P [z:=B])} \)

(9) Axiom: Empty Range: ( \(\star\) x | false : P ) \(\hspace{0.2 cm} \equiv\hspace{0.2 cm} \) u (the identity of \( \star \))

(10) Axiom: One Point Range: ( \(\star\) x | x = E : P ) \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) P[ x := E ]
provided not-occurs-free (x,E)

(11) Axiom: Distributivity: ( \(\star\) x | R : P ) \(\star\) ( \(\star\) x | R : Q ) \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) ( \(\star\) x | R : P \(\star\) Q )
provided each quantification is defined (quantifications with finite ranges are always defined as are quantifications with \(\star\) being either \(\wedge\) or \(\vee\). if \(\star\) is +, then you have to check for convergence of the summation, etc)

(12) Axiom: Range Split 1: ( \(\star\) x | R \(\vee\) S: P ) \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) ( \(\star\) x | R : P ) \(\star\) ( \(\star\) x | S : P )
provided (R \(\wedge\) S) is false \(\wedge\) each quantification is defined

(13) Axiom: Range Split 2: ( \(\star\) x | R \(\vee\) S: P ) \( \star\) ( \(\star\) x | R \(\wedge\) S: P ) \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) ( \(\star\) x | R : P ) \(\star\) ( \(\star\) x | S : P )
provided each quantification is defined

(14) Axiom: Range Split 3: ( \(\star\) x | R \(\vee\) S: P ) \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) ( \(\star\) x | R : P ) \(\star\) ( \(\star\) x | S : P )
provided \(\star\) is idempotent \(\wedge\) each quantification is defined

Note: Definition of idempotent: \(\star\) is idempotent \( \equiv\) ( a \(\star\) a \(\equiv\) a)

(15) Axiom: Interchange of Dummies: ( \(\star\) x | R :( \(\star\) y | S : P) ) \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) ( \(\star\) y | S :( \(\star\) x| R : P) )
provided not-occurs-free(x,S) \(\wedge\) not-occurs-free(y,R) \(\wedge\) each quantification is defined

iow "nested quantifications with the same operator can be interchanged"

(16) Axiom: Dummy Nesting: (\(\star\) x,y | R \(\wedge\) S : P) \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) ( \(\star\) x | R :( \(\star\) y | S : P) )
provided not-occurs-free(y,R)

iow " a single quantification over a list of dummies can be viewed as nested quantification"

(17) Axiom: Dummy Renaming: (\(\star\)x | R : P) \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) (\(\star\)y | R[x := y] : P[x := y])
provided not-occurs-free (y, [R,P])

iow "one dummy can be replaced consistently by another dummy"

(18) Theorem: Change of Dummy (Generalization of Dummy Renaming) (\(\star\)x | R : P) \(\hspace{0.2 cm} \equiv \hspace{0.2 cm}\) (\(\star\)x | R [x := f.y] : P[x := f.y])

provided not-occurs-free (y,[R,P]) \(\wedge\) f is an invertible function such that x = \(f.y\) and y = \(f^{-1}.x\)

Example: Consider (+ \(i\) | 2 \(\leq\) \(i\) \(\leq\) 10 : \(i^2\) ) and we need to have a range starting with zero

the reqd range is (2 - 0) \(\leq\) \(i - 2 \) \(\leq\) (10 - 2)

let k = (i - 2) this is new dummy expressed in terms of old = \(f^{-1}.i\) = k = i - 2

so i = k + 2 this is old dummy expressed in terms of new = \(f.k\) = i = k + 2

\(\hspace{2 cm}\)(+ \(i\) | 2 \(\leq\) \(i\) \(\leq\) 10 : \(i^2\) )
= \(\hspace{0.5 cm}\) Dummy Renaming Theorem. Rename the dummy from i to k with i = f.k = k - 2
\(\hspace{2 cm}\)(+ \(k\) | 2 \(\leq\) \(k+2\) \(\leq\) 10 : \((k+2)^2\) )
= \(\hspace{0.5 cm}\) arithmetic a \(\leq\) b \(\leq\) c \( \equiv \) a-2 \(\leq\) b-2 \(\leq\) c-2
\(\hspace{2 cm}\)(+ \(k\) | 0 \(\leq\) \(k\) \(\leq\) 8 : \((k+2)^2\) )

(19) Theorem: Split off term 1
(\(\star i\) | \(0 \leq i \lt n+1\) : P) \( \equiv \) (\(\star i\) | \(0 \leq i \lt n\) : P) \(\star\) P[i := n ]

(20) Theorem: Split off term 2
(\(\star i\) | \(0 \leq i \lt n+1\) : P) \( \equiv \) P[i := 0 ] \(\star\) (\(\star i\) | \(0 \lt i \lt n + 1\) : P)

Tuesday, October 4, 2011

EQ 8 Proof By Induction

(1) Axiom: Mathematical Induction Over \( \mathcal{N} \). Form 1

( \( \forall \) n:\( \mathcal{N} \) |: ( \( \forall \)i | 0 \( \leq \) i \( \lt \) n: \(P_i\)) \( \Rightarrow \) \(P_n\) ) \( \Rightarrow\) ( \( \forall \) n : \( \mathcal{N} \) : \(P_n\))

used to prove Universal Quantification By Induction


(2) Theorem: Mathematical Induction Over \( \mathcal{N} \). Form 2

( \( \forall \) n:\( \mathcal{N} \) |: ( \( \forall \)i | 0 \( \leq \) i \( \lt \) n: \(P_i\)) \( \Rightarrow \) \(P_n\) ) \( \equiv\) ( \( \forall \) n : \( \mathcal{N} \) : \(P_n\))

used to prove properties of Induction

(3) Theorem: Mathematical Induction Over \( \mathcal{N} \). Form 3

\( P_0\) \( \wedge \) ( \( \forall \) n:\( \mathcal{N} \) |: ( \( \forall \)i | 0 \( \leq \) i \( \leq \) n: \( P_i\) ) \( \Rightarrow \) \( P_{n+1} \) ) \( \Rightarrow\) ( \( \forall \) n : \( \mathcal{N} \) : \(P_n\))

restatement of (1) used for inductive proofs

(4) Parts of Mathematical Induction axiom

\( P_0\) is the base case

( \( \forall \) n:\( \mathcal{N} \) |: ( \( \forall \)i | 0 \( \leq \) i \( \leq \) n: \( P_i\) ) \( \Rightarrow \) \( P_{n+1} \) ) \( \Rightarrow\) ( \( \forall \) n : \( \mathcal{N} \) : \(P_n\)) is the inductive case

( \( \forall \) n:\( \mathcal{N} \) |: ( \( \forall \)i | 0 \( \leq \) i \( \leq \) n: \( P_i\) ) \( \Rightarrow \) \( P_{n+1} \) ) is the inductive hypothesis

(5) Normal Proof Method

(1) Prove Base Case. \( P_0 \)

(2) Assume arbitrary n \( \ge \) 0

(3) Assume Inductive Case ( \( \forall \)i | 0 \( \leq \) i \( \leq \) n: \( P_i\) )

(4) Prove \( P_{n+1} \)


(6) Induction starting at other integers

Let a sequence of integers start at \( n_0 \) Then Inductive Theorem is

\( P_{n_0}\) \( \wedge \) ( \( \forall \) n:\(n_0 \leq n \)|: ( \( \forall \)i | \(n_0 \leq \) i \( \leq \) n: \( P_i\) ) \( \Rightarrow \) \( P_{n+1} \) ) \( \Rightarrow\) ( \( \forall \) n : \(n_0 \leq n \) : \(P_n\))

EQ 7: Leibniz Axiom and Theorems

(1) Axiom, Leibniz: (e = f) \( \Rightarrow \) \( E_e^z = E_f^z \)

Note 1: difference between Leibniz Inference Rule and the Leibniz Axiom.

The inference rule states that if X = Y in all states then \( E_X^z = E_Y^z\) in all states.

The axiom states that if (x = y) in one state then \(E_x^z = E_y^z \) in that state.

Note 2: the implication is one way. iow \( E_e^z = E_f^z \) \( \nRightarrow \) (e = f)

e.g: Let E \( \equiv \) false \( \wedge \) zee . Here \( E_e^z = E_f^z \) but e \( \neq \) f

Substitution Theorems:

If an equality conjuncts or implies, or a conjunction with an equality as a conjunct implies , an Expression E containing one side of the equality, you can replace that part of E with the other side of the equality.

(2) Theorem: Substitution 1: (e = f) \( \wedge\) \( E_e^z \equiv \) (e = f) \( \wedge\) \( E_f^z \)

(3) Theorem: Substitution 2: (e = f) \( \Rightarrow\) \( E_e^z \equiv \) (e = f) \( \Rightarrow\) \( E_f^z \)

(4) Theorem: Substitution 3: q \( \wedge \) (e = f) \( \Rightarrow\) \( E_e^z \equiv \) q \( \wedge \) (e = f) \( \Rightarrow\) \( E_f^z \)

Replace By True Theorems:

If a variable conjuncts or implies, or a conjunction with a variable as a conjunct implies an expression E containing that variable, the occurences of the variable in the expression can be replaced by true

(5) Theorem Replace by true 1: p \( \wedge\) \( E_p^z \equiv \) p \( \wedge\) \( E_{true}^z \)

(6) Theorem: Replace by true 2: p \( \Rightarrow \) \( E_p^z \equiv \) p \( \Rightarrow \) \( E_{true}^z \)

(7) Theorem: Replace by true 3: q \( \wedge \) p \( \Rightarrow \) \( E_p^z \equiv \) q \( \wedge \) p \( \Rightarrow \) \( E_{true}^z \)

Example:

Prove p \( \wedge \) q \( \Rightarrow \) ( p \( \equiv \) q)

\( \hspace{2 cm }\) p \( \wedge \) q \( \Rightarrow \) ( p \( \equiv \) q)

=\( \hspace{0.5 cm } \) recognize pattern. conjunction with a variable (p) on one side implying an expression containing the same variable
\( \hspace{0.5 cm } \) invoke Theorem (6) above, replace p in expression by true

\( \hspace{2 cm }\) p \( \wedge \) q \( \Rightarrow \) ( true \( \equiv \) q)

=\( \hspace{0.5 cm } \) recognize pattern. conjunction with a variable (q) on one side implying an expression containing the same variable
\( \hspace{0.5 cm } \) invoke Theorem (6) above, replace q in expression by true

\( \hspace{2 cm }\) p \( \wedge \) q \( \Rightarrow \) ( true \( \equiv \) true)

=\( \hspace{0.5 cm } \) Theorem: true is the identity of \( \equiv \), m \( \equiv \) m \( \equiv \) true

\( \hspace{2 cm }\) p \( \wedge \) q \( \Rightarrow \) true

=\( \hspace{0.5 cm } \) Theorem: true is the Right Zero of \( \Rightarrow \), m \( \Rightarrow \) true \( \equiv \) true

\( \hspace{2 cm }\) true

Replace By False Theorems:

If an Expression E containing a variable p disjuncts p, implies p or implies a disjunction with p on one side,p can be replaced by false in the expression

(8) Theorem: Replace by False 1: \( E_p^z\) \( \vee \) p \( \equiv \) \( E_{false}^z\) \( \vee \) p

(9) Theorem: Replace by False 2: \( E_p^z\) \( \Rightarrow \) p \( \equiv \) \( E_{false}^z\) \( \Rightarrow \) p

(10) Theorem: Replace by False 2: \( E_p^z\) \( \Rightarrow \) p \(\vee\) q \( \equiv \) \( E_{false}^z\) \( \Rightarrow \) p \(\vee\) q

(11) Theorem: Shannon: \( E_p^z\) \( \equiv \) ( p \(\wedge\) \( E_{true}^z\) ) \(\vee\) ( \( \neg \) p \(\wedge\) \( E_{false}^z\) )

Sunday, October 2, 2011

EQ 6: Monotonicity

(a) Definition.

A function f is monotonic in its argument \( \equiv \) (x \( \Rightarrow \) y) \( \hspace{0.2 cm } \Rightarrow \hspace{0.2 cm } \) (f.x \( \Rightarrow \) f.y)

Note: The textual substitution approach in the Inference Rules provided below are a better way to work out monotonicity etc than a 'function' approach using above idea.

A function is anti-monotonic in its argument \( \equiv \) (x \( \Rightarrow \) y) \( \hspace{0.2 cm } \Rightarrow \hspace{0.2 cm } \) (f.x \( \Leftarrow \) f.y)

(b) Monotonicity of Logical Operators

\( \hspace{0.5 cm } \vee \) Monotonic. (p \( \Rightarrow \) q) \( \hspace{0.2 cm } \Rightarrow \hspace{0.2 cm } \) (p \( \vee \) r) \( \Rightarrow \) (q \( \vee \) r )

\( \hspace{0.5 cm } \wedge \) Monotonic. (p \( \Rightarrow \) q) \( \hspace{0.2 cm } \Rightarrow \hspace{0.2 cm } \) (p \( \wedge \) r) \( \Rightarrow \) (q \( \wedge \) r )

\( \hspace{0.5 cm } \neg \) Antimonotonic. (p \( \Rightarrow \) q) \( \hspace{0.2 cm } \Rightarrow \hspace{0.2 cm } \) ( \( \neg \) p \( \Leftarrow \) \( \neg \) q )

\( \hspace{0.5 cm } \Rightarrow \) Antimonotonic Antecedent. (p \( \Rightarrow \) q) \( \hspace{0.2 cm }\) \( \Rightarrow \) \( \hspace{0.2 cm }\) ( (p \( \Rightarrow \) r) \( \Leftarrow \) (q \( \Rightarrow \) r) )

\( \hspace{0.5 cm } \Rightarrow \) Monotonic Consequent. (p \( \Rightarrow \) q) \( \hspace{0.2 cm }\) \( \Rightarrow \) \( \hspace{0.2 cm }\) ( (r \( \Rightarrow \) p) \( \Rightarrow \) (r \( \Rightarrow \) q) )

\( \hspace{0.5 cm } \forall \) Antimonotonic Range. (a \( \Rightarrow \) b) \( \hspace{0.2 cm }\) \( \Rightarrow \) \( \hspace{0.2 cm }\) ( ( \( \forall \)x | a : P) \( \Leftarrow \) ( \( \forall \)x | b : P))

\( \hspace{0.5 cm } \forall \) Monotonic Body. (a \( \Rightarrow \) b) \( \hspace{0.2 cm }\) \( \Rightarrow \) \( \hspace{0.2 cm }\) ( ( \( \forall \)x | R : a) \( \Rightarrow \) ( \( \forall \)x | R : b))

\( \hspace{0.5 cm } \exists \) Monotonic Range. (a \( \Rightarrow \) b) \( \hspace{0.2 cm }\) \( \Rightarrow \) \( \hspace{0.2 cm }\) ( ( \( \exists \)x | a : P) \( \Rightarrow \) ( \( \exists \)x | b : P))

\( \hspace{0.5 cm } \exists \) Monotonic Body. (a \( \Rightarrow \) b) \( \hspace{0.2 cm }\) \( \Rightarrow \) \( \hspace{0.2 cm }\) ( ( \( \exists \)x | R : a) \( \Rightarrow \) ( \( \exists \)x | R : b))

(c) Capture Avoiding Substitution

( E[z := P ] denotes capture-avoiding substitution: E[z := P ] is a copy of expression E in which all occurrences of *free* variable z have been replaced by expression P , with names of dummies (bound variables) being first replaced to avoid capture.) (Note: best way to avoid this in practice is to have no names in common, bound or not, between P and E. If programming this substitution, then better to rename only bound vars)

(d) Monotonic and Antimonotonic Positions

Consider an occurrence of free variable z in a formula E (but not within an operand of \( \equiv \) ). The *position* of z within E is called monotonic if it is nested within an even number of negations, antecedents, or ranges of universal quantifications; otherwise, it is antimonotonic.

(e) Detailed Method for determining the monotonicity of a position

(1) Replace ( \( \forall \)x | \( F_1 \) : \( F_2 \) ) \( \hspace{0.2 cm }\) by \( \hspace{0.2 cm }\) \( \neg \)( \( \exists \)x | \( F_1 \) : \(\neg F_2 \) )

(2) Replace ( \( \exists \)x | \( F_1 \) : \( F_2 \) ) \( \hspace{0.2 cm }\) by \( \hspace{0.2 cm }\) ( \( \exists \)x |: \( F_1 \wedge F_2 \) )

(3) Replace ( \( F_1 \nLeftarrow F_2 \) ) \( \hspace{0.2 cm }\) by \( \hspace{0.2 cm }\) \( \neg \)( \( F_1 \Leftarrow F_2 \) )

(4) Replace ( \( F_1 \nRightarrow F_2 \) ) \( \hspace{0.2 cm }\) by \( \hspace{0.2 cm }\) \( \neg \)( \( F_1 \Rightarrow F_2 \) )

(5) Replace ( \( F_1 \Leftarrow F_2 \) ) \( \hspace{0.2 cm }\) by \( \hspace{0.2 cm }\) ( \( F_2 \Rightarrow F_1 \) )

(6) Replace ( \( F_1 \Rightarrow F_2 \) ) \( \hspace{0.2 cm }\) by\( \hspace{0.2 cm }\) ( \( \neg F_1 \vee F_2 \) )

(7) Replace ( \( F_1 \wedge F_2 \) ) \( \hspace{0.2 cm }\) by\( \hspace{0.2 cm }\) ( \( \neg (\neg F_1 \vee \neg F_2) \) )

(8) If z is in the second operand \( F_2 \) of ( \( F_1 \vee F_2 \) ), replace ( \( F_1 \vee F_2 \) ) by ( \( F_2 \vee F_1 \) )

(9) Count the number of \( \neg \)s in enclosing z. (the enclosing \( \forall \)s and \( \Rightarrow \)s have been transformed away by steps 1 through 8). If the number is even then positonOf(z) is monotonic and if odd then positionOf(z) is antimonotonic.

(e) MetaTheorem Monotonicity

Suppose P \( \Rightarrow \) Q is a theorem. Let E contain exactly one occurrence of free variable z (but not within an operand of \( \equiv \) ). Then

(a)If postionOf(z) is monotonic, then E[ z := P ] \( \Rightarrow \) E[ z := Q ]
(b)If postionOf(z) is monotonic, then E[ z := P ] \( \Leftarrow \) E[ z := Q ]

This also works if there are multiple occurrences of z, but they all have either monotonic xor antimonotonic positions

(f) Expressing Metatheorem Monotonicity as inference rules

(1) \( \frac{P \Rightarrow Q \hspace{0.2 cm} \wedge \hspace{0.2 cm } position \hspace{0.2 cm } of \hspace{0.2 cm } z \hspace{0.2 cm } is \hspace{0.2 cm } monotonic}{E[ z := P ] \hspace{0.2 cm } \Rightarrow \hspace{0.2 cm } E[ z := Q ]} \)


(2) \( \frac{P \Rightarrow Q \hspace{0.2 cm} \wedge \hspace{0.2 cm } position \hspace{0.2 cm } of \hspace{0.2 cm } z \hspace{0.2 cm } is \hspace{0.2 cm } antimonotonic}{E[ z := P ] \hspace{0.2 cm } \Leftarrow \hspace{0.2 cm } E[ z := Q ]} \)

(g) Convention for citing monotonicity in proofs

\( \hspace{2 cm } (\forall x |: P \wedge R) \)
\( \Rightarrow \hspace{0.5 cm } \) Monotonicity, weakening P \( \Rightarrow \) P \( \vee \) Q
\( \hspace{2 cm } (\forall x |: (P \vee Q) \wedge R) \)

Explanation: Consider \( ( \forall x |: P \wedge R) \) to be E \( \equiv \) \( (\forall x |: z \wedge R) \) and use P \( \Rightarrow \) P \( \vee \) Q as the implication in the Monotonicity Metatheorem. (the position of z is monotonic since it is the body position of a \( \forall \) )

(h) Examples

(1) Given One Point Rule, ie, ( \( \forall \) x | x = E : P) \( \equiv \) P [x := E ] and x does not occur free in E , prove Instantiation theorem, ie, Prove \( (\forall x |: P) \Rightarrow P [ x := E ] \)

Old proof, without monotonicity

LHS \( \hspace{2 cm } (\forall x |: P) \)

= \( \hspace{0.5 cm } \) notation expansion

\( \hspace{2 cm } (\forall x | true : P) \)

= \( \hspace{0.5 cm } \) true \( \equiv a \vee \neg a \)

\( \hspace{2 cm } (\forall x | (x = E) \vee (x \neq E) : P) \)

= \( \hspace{0.5 cm } \) Axiom: Range Split \( (\star | R \vee S: P) \equiv (\star | R : P) \star (\star | S : P) \) here \( \star = \wedge. \) notated as \( \forall \)


\( \hspace{2 cm } (\forall x | (x = E) : P) \wedge (\forall x | (x \neq E) : P) \)

\( \Rightarrow \hspace{0.5 cm } Theorem: a \wedge b \Rightarrow a \)

\( \hspace{2 cm } (\forall x | (x = E) : P) \)

= \( \hspace{0.5 cm } \) Single Point Axiom \( (\star y | (y = F) : Q) \equiv \) Q [ y := F ]

\( \hspace{2 cm } \) P [ x := E ] = RHS.
QED

new proof (using monotonicity)

LHS \( \hspace{2 cm } (\forall x |: P) \)

= \( \hspace{0.5 cm } \) notation expansion

\( \hspace{2 cm } (\forall x | true : P) \)

= \( \hspace{0.5 cm } \) Dummy Renaming ( \( \star \) x | R : P) \( \equiv \) ( \( \star \) y | R[x := y] : P [x := y]) , given y does not occur free in R or P, choose a variable m such that not occurs-free(m, [R, P])

\( \hspace{2 cm } \) ( \( \forall \) m | true : P[x := m])

\( \Rightarrow \hspace{0.5 cm } \) Monotonicity, Right Zero of \( \Rightarrow \) a \( \Rightarrow \) true \( \equiv \) true for any a . Let a = ( m = E) . position of true is anti monotonic

\( \hspace{2 cm }\) ( \(\forall\) m | (m = E) : P[x := m])

= \( \hspace{0.5 cm } \) Single Point theorem, given.

\( \hspace{2 cm }\) P[x := m][m := E]

= \( \hspace{0.5 cm } \) Successive textual replacement

\( \hspace{2 cm } \) P[x := E] QED

Note: implications with true or false in them are useful.

Example 2: All men are mortal, Socrates is a man. Therefore Socrates is mortal.

step 1: establish notation.

man.m : person m is a man
mortal.m : person m is a mortal
S : Socrates

step 2: formalize English to logic

( \( \forall \) m |: man.m \( \Rightarrow \) mortal.m) \( \wedge \) man.S \( \Rightarrow \) mortal.S

step 3: prove

LHS \( \hspace{2 cm } \) ( \( \forall \) m |: man.m \( \Rightarrow \) mortal.m) \( \wedge \) man.S \( \Rightarrow \) mortal.S

\( \Rightarrow \hspace{0.5 cm } \) Monotonicity, Instantiation \( (\forall x |: P) \Rightarrow P [ x := e ] \), e = S, \( \wedge \) is monotonic in both arguments

\( \hspace{2 cm } \) (man.S \( \Rightarrow \) mortal.S) \( \wedge \) man.S

\( \Rightarrow \hspace{0.5 cm } \) Modus Ponens

\( \hspace{2 cm } \) mortal.S QED

Example 3

Prove

None but those with hearts can love. Some liars are heartless. Some liars cannot love

Step 1:Establish notation

hh.p = p has a heart
cl.p = p can love
li.p = p is a liar

Step 2: Translate English to logic
( \( \forall \) p|: \( \neg \)hh.p \( \Rightarrow \) \( \neg \) cl.p ) \( \wedge \) ( \( \exists \)x |: li.x \( \wedge \) \( \neg \) hh.x ) \( \Rightarrow \) ( \( \exists \) y |: li.y \( \wedge \neg\) cl.y)

Step 3 Prove

LHS \( \hspace{2 cm } \) ( \( \forall \) p|: \( \neg \)hh.p \( \Rightarrow \) \( \neg \) cl.p ) \( \wedge \) ( \( \exists \)x |: li.x \( \wedge \) \( \neg \) hh.x )

= \( \hspace{0.5 cm } \) Theorem: Contrapositive p \( \Rightarrow \) q \( \hspace{0.2 cm } \)\( \equiv \)\( \hspace{0.2 cm } \) \( \neg \)q \( \Rightarrow \) \( \neg \) p

\( \hspace{2 cm } \) ( \( \forall \) p|: cl.p \( \Rightarrow \) hh.p ) \( \wedge \) ( \( \exists \)x |: li.x \( \wedge \) \( \neg \) hh.x )

= \( \hspace{0.5 cm } \) Theorem Distribution of \( \wedge \) over \( \exists \), P \( \wedge \) ( \( \exists \) x | R : Q ) \( \equiv \) ( \( \exists \) x | R : P \( \wedge \) Q )

\( \hspace{2 cm } \) ( \( \exists \)x |: ( \( \forall \) p|: cl.p \( \Rightarrow \) hh.p ) \( \wedge \) li.x \( \wedge \) \( \neg \) hh.x )



= \( \hspace{0.5 cm } \) Monotonicity, Instantiation with (p = x), \( \wedge \) is monotonic in both arguments

\( \hspace{2 cm } \) ( \( \exists \) x|: (cl.x \( \Rightarrow \) hh.x) \( \wedge \) li.x \( \wedge \) \( \neg \) hh.x )

= \( \hspace{0.5 cm } \) Theorem: Contrapositive p \( \Rightarrow \) q \( \hspace{0.2 cm } \)\( \equiv \)\( \hspace{0.2 cm } \) \( \neg \)q \( \Rightarrow \) \( \neg \) p

\( \hspace{2 cm } \) ( \( \exists \) x |: (\( \neg \) hh.x \( \Rightarrow \) \( \neg \) cl.x) \( \wedge \) li.x \( \wedge \) \( \neg \) hh.x )

\( \hspace{0.5 cm } \) \( \Rightarrow \hspace{0.5 cm } \) Modus Ponens

\( \hspace{2 cm } \) ( \( \exists \) x |: \( \neg \) cl.x \( \wedge \) li.x)

= \( \hspace{0.5 cm } \) Translate to English

\( \hspace{2 cm } \) There exists some people who are liars and also can't love = Some liars can't love QED

EQ 5 Implication Axioms and Theorems

(1) Axiom: Definition of Implication: p \( \Rightarrow \) q \( \hspace{0.2 cm } \)\( \equiv \)\( \hspace{0.2 cm } \) p \( \vee \) q \( \equiv \) q

(2) Axiom: Consequence p \( \Leftarrow \) q \( \hspace{0.2 cm } \)\( \equiv \)\( \hspace{0.2 cm } \) q \( \Rightarrow \) p

(3) Theorem: Definition of Implication p \( \Rightarrow \) q \( \hspace{0.2 cm } \)\( \equiv \)\( \hspace{0.2 cm }\) \( \neg \)p \( \vee \) q

(4) Theorem: Definition of Implication: p \( \Rightarrow \) q \( \hspace{0.2 cm } \)\( \equiv \)\( \hspace{0.2 cm } \) p \( \wedge \) q \( \equiv \) p

(5) Theorem: Contrapositive p \( \Rightarrow \) q \( \hspace{0.2 cm } \)\( \equiv \)\( \hspace{0.2 cm } \) \( \neg \)q \( \Rightarrow \) \( \neg \) p

(6) Theorem: p \( \Rightarrow \) (q \( \equiv \) r)\( \hspace{0.2 cm } \)\( \equiv \)\( \hspace{0.2 cm } \) p \( \wedge\) q \( \equiv \) p \( \wedge \) r

(7) Theorem: Distributivity \( \frac{\Rightarrow}{\equiv} \) p \( \Rightarrow \) (q \( \equiv \) r) \( \hspace{0.2 cm } \)\( \equiv \)\( \hspace{0.2 cm } \) p \( \Rightarrow \) q \( \equiv \) p \( \Rightarrow \) r

(8) Theorem: Distributivity \( \frac{\Rightarrow}{\Rightarrow} \) p \( \Rightarrow \) (q \( \Rightarrow \) r) \( \hspace{0.2 cm } \)\( \equiv \)\( \hspace{0.2 cm } \) (p \( \Rightarrow \) q) \( \Rightarrow \) (p \( \Rightarrow \) r)

(9) Theorem: Shunting p \( \wedge \) q \( \Rightarrow \) r \( \hspace{0.2 cm } \)\( \equiv \)\( \hspace{0.2 cm } \) p \( \Rightarrow \) (q \( \Rightarrow \) r )

(10) Theorem: p \( \wedge \) ( p \( \Rightarrow \) q ) \( \hspace{0.2 cm } \)\( \equiv \)\( \hspace{0.2 cm } \) p \( \wedge \) q

(11) Theorem: p \( \wedge \) ( q \( \Rightarrow \) p) \( \hspace{0.2 cm } \)\( \equiv \)\( \hspace{0.2 cm } \) p

(12) Theorem: p \( \vee \) ( p \( \Rightarrow \) q ) \( \hspace{0.2 cm } \)\( \equiv \)\( \hspace{0.2 cm } \) true

(13) Theorem: p \( \vee \) ( q \( \Rightarrow \) p) \( \hspace{0.2 cm } \)\( \equiv \)\( \hspace{0.2 cm } \) q \( \Rightarrow \) p

(14) Theorem: p \( \vee \) q \( \hspace{0.2 cm } \)\( \Rightarrow \)\( \hspace{0.2 cm } \) p \( \wedge \) q \( \equiv \) p \( \equiv \) q

(15) Reflexivity of \( \Rightarrow \) : p \( \Rightarrow \) p \( \hspace{0.2 cm } \)\( \equiv \)\( \hspace{0.2 cm } \) true

(16) Theorem: Right Zero of \( \Rightarrow \) : p \( \Rightarrow \) true \( \hspace{0.2 cm } \)\( \equiv \)\( \hspace{0.2 cm } \) true

(17) Theorem: Left Identity of \( \Rightarrow \) : true \( \Rightarrow \) p \( \hspace{0.2 cm } \)\( \equiv \)\( \hspace{0.2 cm } \) p

(18) Theorem: p \( \Rightarrow \) false \( \hspace{0.2 cm } \)\( \equiv \)\( \hspace{0.2 cm } \) \( \neg \)p


(19) Theorem: false \( \Rightarrow \) p \( \hspace{0.2 cm } \)\( \equiv \)\( \hspace{0.2 cm } \) true

Weakening and Strengthening Theorems

(20) Theorem: p \( \hspace{0.2 cm } \) \( \Rightarrow \) \( \hspace{0.2 cm } \) p \( \vee \) q

(21) Theorem: p \( \wedge \) q \( \hspace{0.2 cm } \) \( \Rightarrow \) \( \hspace{0.2 cm } \) p

(22) Theorem: p \( \wedge \) q \( \hspace{0.2 cm } \) \( \Rightarrow \) \( \hspace{0.2 cm } \) p \( \vee \) q

(23) Theorem: p \( \wedge \) q \( \hspace{0.2 cm } \) \( \Rightarrow \) \( \hspace{0.2 cm } \) p \( \wedge \) (q \( \vee \) r)

(24) Theorem: p \( \vee \) (q \( \wedge \) r) \( \hspace{0.2 cm } \) \( \Rightarrow \) \( \hspace{0.2 cm } \) p \( \vee \) q




(25) Theorem: Modus Ponens p \( \wedge \) ( p \( \Rightarrow \) q) \( \hspace{0.2 cm } \) \( \Rightarrow \) \( \hspace{0.2 cm } \) q

(26) Theorem : (p \( \Rightarrow \) r) \( \wedge \) (q \( \Rightarrow \) r) \( \hspace{0.2 cm } \) \( \equiv \) \( \hspace{0.2 cm } \) ( p \( \vee \) q \( \Rightarrow \) r)

(27) Theorem : (p \( \Rightarrow \) r) \( \wedge \) ( \( \neg \)p \( \Rightarrow \) r) \( \hspace{0.2 cm } \) \( \equiv \) \( \hspace{0.2 cm } \) r

(28) Theorem: Mutual Implication (p \( \Rightarrow \) q) \( \wedge \) (q \( \Rightarrow \) p) \( \hspace{0.2 cm } \) \( \equiv \) \( \hspace{0.2 cm } \) ( p \( \equiv \) q)

(29) Theorem: Anti-Symmetry (p \( \Rightarrow \) q) \( \wedge \) (q \( \Rightarrow \) p) \( \hspace{0.2 cm } \) \( \Rightarrow \) \( \hspace{0.2 cm } \) ( p \( \equiv \) q)

(30) Theorem: Transitivity (1) (p \( \Rightarrow \) q) \( \wedge \) (q \( \Rightarrow \) r) \( \hspace{0.2 cm } \) \( \Rightarrow \) \( \hspace{0.2 cm } \) (p \( \Rightarrow \) r)

(31) Theorem: Transitivity (2) (p \( \equiv \) q) \( \wedge \) (q \( \Rightarrow \) r) \( \hspace{0.2 cm } \) \( \Rightarrow \) \( \hspace{0.2 cm } \) (p \( \Rightarrow \) r)

(32) Theorem: Transitivity (3) (p \( \Rightarrow \) q) \( \wedge \) (q \( \equiv \) r) \( \hspace{0.2 cm } \) \( \Rightarrow \) \( \hspace{0.2 cm } \) (p \( \Rightarrow \) r)

Other useful Implication Theorems

(33) Theorem: p \( \Rightarrow \) ( q \( \Rightarrow \) p) \( \hspace{0.2 cm } \) \( \Rightarrow \) \( \hspace{0.2 cm } \) true

(34) Theorem (p \( \Rightarrow \) q) \( \hspace{0.2 cm } \) \( \Rightarrow \) \( \hspace{0.2 cm } \) (p \( \wedge \) r) \( \Rightarrow \) (q \( \wedge \) r)

(35) Theorem (p \( \Rightarrow \) q) \( \wedge \) (r \( \Rightarrow \) s) \( \hspace{0.2 cm } \) \( \Rightarrow \) \( \hspace{0.2 cm } \) (p \( \vee \) r) \( \Rightarrow \) (q \( \vee \) s)

(36) Theorem (p \( \Rightarrow \) q) \( \wedge \) (r \( \Rightarrow \) s) \( \hspace{0.2 cm } \) \( \Rightarrow \) \( \hspace{0.2 cm } \) (p \( \wedge \) r) \( \Rightarrow \) (q \( \wedge \) s)

(37) Theorem a \( \Rightarrow \) \( \neg \)b \( \hspace{0.2 cm } \) \( \equiv \) \( \hspace{0.2 cm } \) a \( \Rightarrow \) b \( \equiv \) \( \neg \)a

(38) Theorem \( \neg \)a \( \Rightarrow \) b \( \hspace{0.2 cm } \) \( \equiv \) \( \hspace{0.2 cm } \) a \( \Rightarrow \) b \( \equiv \) b

Saturday, October 1, 2011

EQ 4 Equality vs Equivalence

b \( \equiv\) c is evaluated the same as b = c (in terms of truth tables) except that \( \equiv \) is allowed only when b and c are booleans.

Definition of Conjunctional

If \( \circ \) and \( \star \) are conjunctional operators, b \( \circ \) c \( \star \) d is equivalent to b \( \circ \) c \( \wedge \) c \( \star \) d.

From the precedence table, all operators on line 10 are conjunctional, ie = < > \( \epsilon \) \( \subset \) \( \subseteq \) \( \supset \) \( \supseteq \) | are all conjunctional

Definition of Associative

Binary Operator \( \circ \) is associative \( \equiv \) ((b \( \circ \) c) \( \circ \) d) = (b \( \circ \) ( c \( \circ \) d ))

Key 1: \( \equiv \) is associative, = is conjunctional
Key 2: Conjunctional use of = (and other conjunctional operators ) are syntactic sugar.

Conversion back and forth:


\( \hspace{2 cm }\) b \( \equiv \) c \( \equiv \) d

= \( \hspace{0.5 cm } \) parenthesize

\( \hspace{2 cm }\) (b \( \equiv \) c ) \( \equiv \) d

= \( \hspace{0.5 cm } \) replace operator

\( \hspace{2 cm } \) (b = c) = d

and

\( \hspace{2 cm }\) b = c = d
= \( \hspace{0.5 cm } \) remove conjunctional syntactic sugar
\( \hspace{2 cm }\) b = c \( \wedge \) c = d
= \( \hspace{0.5 cm } \) parenthesize
\( \hspace{2 cm }\) (b = c) \( \wedge \) (c = d)
= \( \hspace{0.5 cm } \) replace operator
\( \hspace{2 cm }\) (b \( \equiv \) c) \( \wedge \) (c \( \equiv \) d)

EQ 3: Inference Rules

The logic EQ has four inference rules

(1) Substitution

\( \frac{E}{E[v := F]} \)

where E is an expression, v is a list of variables and F is a corresponding list of expressions.

Iow, if E is a theorem, so is E with all the variables in V replaced by the corresponding expressions in F.

E.g: Let E be 2.x/2 = x be a theorem.

Then by substitution, so is 2.(j + 5) / 2 = j + 5 where v=x and E = j+5


(2) Leibniz

\( \frac{X=Y}{E[z:=X]=E[z:=Y]} \)

NB: z is a variable, NOT an expression.

Two ways of looking at Leibniz


(A) Given an equality X = Y and an expression E,

(1) Choose a variable z within E
(2) Replace the equality with a new equality with z replaced by X on one side and Y on the other

(B) Given E,

(1) spot an *expression X* (NOT variable ) within E that needs replacement
(2) Find an equality X = Y
(3) consider the given expression E to be actually E [z := X]
(4) Use Leibniz with the equality (from (2) ) to get E [z := Y]

this is written as
\( \hspace{2 cm } E[z:=X] \)
= \( \hspace{0.5 cm } \) Leibniz. z is z. X = Y
\( \hspace{2 cm } E[z:=Y \)

eg:

Given m = 2j (note: this is the equality X = Y) and E is m/2 = 2.(j - 1) prove that 2j/2 = 2(j-1)

Leibniz usage B: m on the LHS of E needs to be replaced with 2j, so we look for an equality with m on the left side, which we find in the given equality. If we consider the LHS of E to be E[z := m], then

\( \hspace{2 cm } m/2 = 2(j - 1) \)
= \( \hspace{0.5 cm } \) Leibniz. z is m, m = 2j
\( \hspace{2 cm } 2j/2 = 2(j - 1) \)




(C) Combined use of Substitution and Leibniz

Strictly speaking, Substitution and Leibniz are distinct inference rules and the two should be used distinctly



Given we know that 2x/2 = x (note: this is the equality X=Y)

let E be 2j/2 = 2(j+1). prove j = 2(j-1 )

(separate use of Substitution and Leibniz)
\( \hspace{2 cm }E \equiv \) 2j/2 = 2(j - 1)
= \( \hspace{0.5 cm } \) Substitution j := x
\( \hspace{2 cm }\) 2x/2 = 2(x - 1)
= \( \hspace{0.5 cm } \) Leibniz z is 2x/2 with equality 2x/2 = x
\( \hspace{2 cm } \) x = 2(x - 1)
= \( \hspace{0.5 cm } \) Substitution x := j
\( \hspace{2 cm } \)j = 2(j - 1) QED


(simultaneous use of Substitution and Leibniz collapses some steps)
\( \hspace{2 cm }E \equiv \) 2j/2 = 2(j - 1)
= \( \hspace{0.5 cm } \) Substitution and Leibniz 2x/2:= x
\( \hspace{2 cm } \)j = 2(j - 1) QED

(3) Transitivity

\( \frac{X=Y,Y=Z}{X=Z} \)

iow if X = Y and Y = Z are theorems, so is X = Z

(4) Equanimity

\( \frac{E,E=F}{F} \)


iow a theorem is either an axiom or the result of an inference rule where the premises are axioms

Example for use of all 4 inference rules

Prove that \( \neg p \equiv p \equiv false \)

Proof:

(0) \( \hspace{2 cm } \neg p \equiv p \equiv false \)
(1) = \( \hspace{0.5 cm } \) Leibniz and Substitution with Theorem \(\neg (x \equiv y) \equiv \neg x \equiv y \) used in the reverse direction, substituting x,y := p,p and z = \(\neg p \equiv p \)
(2) \( \hspace{2 cm } \neg (p \equiv p) \equiv\) false
(3) = \( \hspace{0.5 cm } \) Leib + Sub using Theorem Identity of \( \equiv \),\( x \equiv x \equiv \) true , z is p \( \equiv \) p, and x := p
(4) \( \hspace{2 cm } \neg true \equiv false \)
(3) = \( \hspace{0.5 cm } \) is an Axiom and therefore
(5) \( \hspace{2 cm } \) true QED

and since (0) = (2) and (2) = (4) and (4) = (5), by Transitivity (0) = (4)

and since (0) = (4) and (4) is a theorem, (0) is a theorem by Equanimity.

Friday, September 23, 2011

EQ 2: Textual Replacement

prev: Table of Precedences


E [x := R] or \(E _{R} ^{x} \) denotes an expression that is the same as E, but with all the occurrences of x replaced by "(R)". Unnecessary parentheses maybe removed after substitution.

e.g: (z + y) [z := 5] becomes ((5) + y) becomes (by removing unnecessary parentheses) (5 + y)

If x is a list of *distinct* \( x_1, x_2,...x_n\) of variables and R a list \(R_1\ , R_2 , ... R_n\) of expressions then \(E _{R} ^{x} \) denotes the *simultaneous* replacement in E of the variables of x by corresponding expressions of R, each expression being enclosed by parentheses.

(z + y) [z,y := 5,6] becomes ((5) + (6)) becomes (by removing unnecessary parentheses) (5 + 6)

next: Inference Rules

EQ 1: Precedences

Precedences (from high to low)

(1) [x := e] (Textual Substitution)

(2) . (function application)

(3) Unary Prefix Operators + - \( \neg \) # ~ \( \mathcal { P } \)

(4) **

(5) \( \ast \) / \( \div \) mod gcd

(6) + - \( \cup \) \( \cap \) \( \times \) \( \circ \) \( \bullet \)

(7) \( \downarrow \) \( \uparrow \)

(8) #

(9) \( \triangleright \) \( \triangleleft \) ^

(10) = < > \( \epsilon \) \( \subset \) \( \subseteq \) \( \supset \) \( \supseteq \) |

(11) \( \vee \) \( \wedge \)

(12) \( \Rightarrow \) \( \Leftarrow \)

(13) \( \equiv \)

Notes: All non associative prefix binary operators associate to the left, except ** , \( \triangleleft \) and \( \Rightarrow \) which associate to the right.


All operators on lines 10, 12 and 13 may have a slash / through them to denote negation.

Thus b \( \not\equiv \) c is equivalent to \( \neg \) ( b \( \equiv \) c )


A core subset of the above, omitting unnecessary symbols, which is used to prove the theorems of the logic itself is as follows

(a) [x := e] (Textual Substitution)

(b) . (function application)

(c) \( \neg \)

(d) \( \ast \) /

(e) =

(f) \( \vee \) \( \wedge \)

(g) \( \Rightarrow \) \( \Leftarrow \)

(h) \( \equiv \)

prev: next: Textual Substitution